$\frac{8 - x}{4 - x}$ = 3;
8 - x = 12 - 3x
2x = 4; x = 2
also
$\frac{10 -y}{4 - y}$ = 3;
10 - y = 12 - 3y
2y = 2; y = 1
Co-ordinate of the centre of enlargement is O(2, 1)
johnmulu answered the question on March 2, 2017 at 08:58
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