L = 5y + 2x + 8 = 0
5y = -2x - 8; y = -$\frac{2x}{5}-\frac{8}{5}$
Gradient m1 = -$\frac{2}{5}$
Gradient of the line passing
through (-5, 0) and (5, -4)
$\frac{y -y_1}{x - x_1}$ = $\frac{-4 - 0}{5--5}$ = -$\frac{4}{10}$ = -$\frac{2}{5}$
Gradient m2 = -$\frac{2}{5}$
for parallel lines m1 = m2
johnmulu answered the question on March 7, 2017 at 08:08
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