Calculate the area enclosed between the curve y = 6x - x², x - axis and the lines x = 1 and x = 5 using the mid-ordinate rule with four strips

Calculate the area enclosed between the curve y = 6x - x², x - axis and the lines x = 1 and x = 5 using the mid-ordinate rule with four strips

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h = $\frac{5 \;-\;1}{4}$ = $\frac{4}{4}$ = 1

for x 1,2,3,4,5

Mid-ordinate are 1.5,2.5,3.5 and 4.5

y = 6x - x²

when x = 1.5

y = 6(1.5) - (1.5)² = 9-2.25 = 6.75

x = 2.5,

y = 6(3.5) - (3.5)² = 21-12.25

= 8.75
x = 3,5

y = 6(4.5)-(4.5)² = 27 - 20.25

= 6.75

(for y ordinates)

area using mid-ordinate rule

=h(sum of ordinates)

= 1(6.75 + 8.75 + 8.75 + 6.75)

= 31 sq. units

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johnmulu answered the question on March 8, 2017 at 09:52

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