i) I. Wavelength = 5 – 1 = 4 cm
II. Amplitude = 2 cm
ii) I. Periodic time, T = $\frac{0.09}{2.25}$ = 0.04 s
F = $\frac{1}{T}$ = $\frac{1}{0.04}$ = 25Hz
II. V = 25 x 0.04 = 1 ms-1
johnmulu answered the question on April 19, 2017 at 12:44
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The three springs shown in figure 7 are identical and have negligible weight. The extension produced on the system of springs is 20 cm.
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Date posted:
April 19, 2017
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Answers (1)
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Date posted:
April 19, 2017
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Date posted:
April 19, 2017
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Answers (1)
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April 19, 2017
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April 19, 2017
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April 19, 2017
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Date posted:
April 19, 2017
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Date posted:
April 19, 2017
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April 19, 2017
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Date posted:
April 19, 2017
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Date posted:
April 19, 2017
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Date posted:
April 19, 2017
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Date posted:
April 19, 2017
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Answers (1)
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Date posted:
April 19, 2017
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Answers (1)
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(Solved)
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Date posted:
April 19, 2017
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(Solved)
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Date posted:
April 19, 2017
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Answers (1)
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Answers (1)
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Date posted:
April 19, 2017
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Date posted:
April 19, 2017
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Answers (1)