since cursor positioning functions differ from compiler to compiler and environment to environment, only one possible solution is shown for borland C++ under a command-prompt environment.
#include
#include
using namespace std;
void myclreol(int len =- 1);
int main()
{
int i;
gotoxy(1, 1);
for(i=0; i<24; i++)
cout << "abcdefghijklmnopqrstuvwxyz1234567890\n";otoxy(1, 2);
myclreol();
gotoxy(1, 4);
myclreol(20);
return 0;
}
//clear to end line unless len parameter is specified.
void myclreol(int len)
{
int y;
x = wherex(); // get x position
y = wherey() // get y position
if(len== -1) len = 80-x;
int i = x;
for(; i<=len; i++) cout << ' ';
gotoxy(x, y); //reset the cursor
}
Githiari answered the question on May 31, 2018 at 17:39
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In the C++ standard library is the function strtol(), which has this prototype:
long strtol|(const char*start, const **end, int base);
The function cnverts the numeric string...
(Solved)
In the C++ standard library is the function strtol(), which has this prototype:
long strtol|(const char*start, const **end, int base);
The function cnverts the numeric string pointed to by start into a long integer. The number base of the numeric string is specified by base. Upon return, end points to the character in the string immediately following the end of the number. The long integer equivalent of the numeric string is returned. base must be in the range 2 to 38. However, most commonly, base 10 is used.
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Date posted:
May 31, 2018
.
Answers (1)
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#include
using namespace...
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#include
using namespace std;
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Date posted:
May 31, 2018
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Answers (1)
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Date posted:
May 31, 2018
.
Answers (1)
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