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Two girls are running and the first girl is ahead by 15m. The first girl is running at 8m/s while the second girl is running at...

      

Two girls are running and the first girl is ahead by 15m. The first girl is running at 8m/s while the second girl is running at 12m/s. At what distance will the second girl over take the first girl?

  

Answers


Andrew
Assuming the second girl overtakes the first girl at distance x;

therefore at x, Second girl covers x metres at 12m/s,
Distance= xm
Speed= 12m/s
Time= Distance/Speed
= xm/12m/s
=(x/12)s

After (x/12) seconds, First will cover (x-15)m at 8m/s,
therefore;
Distance= (x-15)m
Speed= 8m/s
Time= (x/12)s

but Distance= Speed*Time
(x-15)m= 8m/s*(x/12)s
12x-180= 8x
12x-8x= 180
4x= 180
x= 45
x= 45m.
The second girl will overtake the first girl at 45m.
Andreaz answered the question on August 20, 2018 at 13:53


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