2NaOH + H2SO4 = Na2SO4 + 2H2O
moles of H2SO4 in dm3 = Mass of H2SO4 /RFM of H2SO4
mass of H2SO4 = 49
RFM of H2SO4 = 98
Moles =49/98
=0.5 moles
Moles of H2SO4 in 200 cm3 = (0.5 x 200)/1000
=0.1 moles
From the chemical equation above, 2mole of NaOH neutralizes 1moles of H2SO4.
Therefore, moles of NaOH that neutralizes 0.1 moles of H2SO4 = (0.1 x 2)/1
=0.2 moles
Mr Masinde answered the question on June 21, 2018 at 15:00
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