Solve for x in:

Solve for x in:
$x\;+\;2 = \frac{5x\;-\;1}{4}-\frac{1}{2}(x\;+\;1)$

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$x\;+\;2\;=\; \frac{5x\;+\;1}{4}\;-\frac{1}{2}(x\;+\;1)$

$x\;+\;2$ = $\frac{1(5x\;+\;1)\;-2(x\;+\;1)}{4}$

$x\;+\;2$ = $\frac{5x\;+\;1\;-\;2x\;-2}{4}$

4x + 8 = 3x - 1

combine the like terms

4x - 3x = -1 - 8;

x = -9

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johnmulu answered the question on June 7, 2017 at 11:51

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