$\frac{x\;+\;1}{3} \;- \frac{x\;-\;2}{4} \;=\frac{x}{6}$
L.C.M of 3 and 4 is 12
$\frac{4x\;+\;4\;-\;3x\;+\;6}{12}$ = $\frac{x}{6}$
$\frac{x\;+\;10}{12}\;=\; \frac{x}{10}$
Cross multiply to get
6x + 60 = 12x
60 = 6x;
x = 10
johnmulu answered the question on June 7, 2017 at 12:43
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