A vertical object 5 cm high is placed 10 cm in front of a convex mirror of focal length 15 cm. find the position, size...

A vertical object 5 cm high is placed 10 cm in front of a convex mirror of focal length 15 cm. find the position, size and nature of image formed. Determine the magnification of the image.

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Let 1 cm represent 5 cm, then the focal length = 3 cm, object size = 1 cm Object distance = 2 cm.

From the scale drawing, Image position = 1.2 cm × 5 = 6.0 cm behind the mirror.
Image size = 0.6 cm × 5 = 3.0 cm.
The image is virtual and erect.
Magnification = image dist. / object dist.
Hence 6 /10 = 0.6 (diminished).

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Mutiso answered the question on October 12, 2018 at 07:40

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