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A block of metal of volume 60 cm³ weighs 4.80 N in air. Determine its weight when fully submerged in a liquid of density 1,200...

A block of metal of volume 60 cm³ weighs 4.80 N in air. Determine its weight when fully submerged in a liquid of density 1,200 kgm^-3.

Answers

Volume of liquid displaced = 60 cm³ = 6.0 × 10^-5 m³.
Weight of the displaced liquid = volume × density × gravity = v × p × g
= 6.0 × 10^-5 × 1200 × 10
= 0.72 N
Upthrust = weight of the liquid displaced.
Weight of the block in the liquid = (4.80 – 0.72) = 4.08 N.

Mutiso answered the question on October 16, 2018 at 06:32

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