Simplify

Simplify $\sqrt{3^x \times 4^{2x }\div3^{-x}}$

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= ($3^x \times 4^{2x} \div 3^{-x})^{\frac{1}{2}}$

= $(3^{x+x}+4^{2x})^{\frac{1}{2}}$ = $(3^{2x} \times 4^{2x})^{\frac{1}{2}}$

=$3^x \times 4^x = 12^x$

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johnmulu answered the question on June 12, 2017 at 08:43

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