Solve for x in

Solve for x in 9^x + 3^2x+1 = 36

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9^x + 3^2x+1 = 36

3^2x + 3^2x+1 = 36

3^2x + 3^2x x 3¹ = 36

3^2x (1 + 3) = 36

3^2x(4) = 36

Divide both sides by 4; 3^2x = 9

Express both sides to same

base; 3^2x = 3²

Equate the powers

2x = 2;

x = 1

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johnmulu answered the question on June 12, 2017 at 12:44

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