Trusted by millions of Kenyans
LoginRegister
Study resources on Kenyaplex

Get ready-made curriculum aligned revision materials

Exam papers, notes, holiday assignments and topical questions – all aligned to the Kenyan curriculum.

Browse exam papers
Or go directly to:
Class notes Holiday assignments Topical questions Other resources

A right angled solid of dimensions 0.02m by 0.02m by 0.2m and density 2,700kg/m3 is supported inside kerosene of density 800kg/m3 by a thread which...

A right angled solid of dimensions 0.02m by 0.02m by 0.2m and density 2,700kg/m3 is supported inside kerosene of density 800kg/m3 by a thread which is attached to a spring balance. The long side is vertical and the upper surface is 0.1m below the surface of the kerosene.

i) Calculate the force due to the liquid on the lower upper surface of the solid.
ii) Calculate the up thrust and determine the reading on the spring balance.

Answers

Wilfred
(i)
Lower surface of solid
P = gh
Force = P x A = gh x A
= 800 x 10 x 0.5 x 4 x 10-4
= 0.96N

Upper surface of solid.
Force = P x A = gh x A
= 800 x 10 x 0.1 x 4 x 10-4
= 0.32N

(ii)
Upthrust = 0.96 – 0.32 = 0.6N
Weight of the solid = Density x Volume x g
= 2.7 x 103 x 0.2 x 104 x 4 x 10
= 2.16

Balance reading = 2.16 – 0.64
= 1.52N
Wilfykil answered the question on March 27, 2019 at 07:04

Answer Attachments

Next: Use the set up below to answer the questions that follow.

Previous: Use the bond energy value given below for the question that follows. Bond ...

View more Physics Questions and Answers  |  Return to Questions Index

Exams With Marking Schemes

Related Questions