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Describe the reaction of sulphur (VI) oxide with chlorine

Describe the reaction of sulphur (VI) oxide with chlorine.

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Kavungya
Sulphur (IV) oxide reacts with moist chlorine to form an acidic mixture of sulphuric (VI) acid and hydrochloric acid.
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Explanation:
- Sulphur (IV) oxide serves as the reducing agent reducing chlorine into hydrochloric acid;
- Chlorine acts as the oxidizing agent; oxidizing the sulphur (IV) oxide into sulphuric (VI) acid
Kavungya answered the question on April 29, 2019 at 13:11

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