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In the figure below EFGH is a rhombus and FGJ is a triangle. Angle GFJ = 56° and JGH is a straight line. Line JG...

In the figure below EFGH is a rhombus and FGJ is a triangle. Angle GFJ = 56° and JGH is a straight line. Line JG = line GH.

What is the size of angle HEF?

A. 68°
B. 90°
C. 112°
D. 124°

Answers

The correct answer is [C]

Since FEGH is a rhombus then
GH =GF =GJ
Triangle FGJ is an isosceles triangle.
Angle GJF = GFJ = 56⁰
JGF = 180-56 = 68⁰
=112⁰

Wilfykil answered the question on July 29, 2019 at 08:37

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