A transistor is connected in common emitter (CE) configuration in which collector supply is 8V and the voltage drop across resistance R_C connected in the...

A transistor is connected in common emitter (CE) configuration in which collector supply is 8V and the voltage drop across resistance R_C connected in the collector circuit is 0.5V. The value of R_C = 800 ohms. If α = 0.96, determine:

(i) collector-emitter voltage
(ii) base current

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Fig. 4.22 shows the required common emitter connection with various values.
(i) Collector-emitter voltage, V_CE = V_CC - 0.5 = 8 - 0.5 = 7.5 V
(ii) The voltage drop across R_C (= 800 ohms ) is 0.5 V.

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Wilfykil answered the question on August 14, 2019 at 13:31

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