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The set-up below was used to electrolyse molten lead (II) iodine

The set-up below was used to electrolyse molten lead (II) iodine
17cmoltenlead42420171034.jpg
i) State the observation that was made at the anode during the electrolysis. Give a reason for your answer.
ii) A current of 0.5 A was passed for two hours. Calculate the mass of lead that was deposited (pb = 2071F = 9, 500C)

Answers


John
i) purple fumes are produced since Iodine is produced at the anode

ii) Quantity of electricity = It

= 0.5 x 2 x 60 x 60

= 3600 c

Mass of pb = $\frac{3600 \times 207}{2 \times 96500}$

= 3.861 g
johnmulu answered the question on April 27, 2017 at 08:07

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