Mid point = (\frac{x_1 + x_2}{2}, $\frac{y_1+y_2}{2}$)
(4,3) = (\frac{x+6}{2},$\frac{y+5}{2}$)
$\frac{x+6}{2}$ = 3;
y = 5 = 6;
Y = 1
co-ordinates of A are (2,1)
johnmulu answered the question on June 13, 2017 at 07:35
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