Describe the reduction of concentrated nitric (V) acid by sulphur (VI) oxide.

Describe the reduction of concentrated nitric (V) acid by sulphur (VI) oxide.

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Procedure
- Sulphur (IV) oxide is bubbled through (into) a solution of concentrated nitric (v) acid.
Observation
- Brown fumes (of NO₂) are liberated.
Explanation
- Sulphur (IV) oxide reduces nitric (V) acid to nitrogen (IV) oxide (brown) while it is itself oxidized by HNO₃ to form H₂SO₄.
- Thus while SO₂ is the reducing agent; HNO₃ is the oxidizing agent.

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Kavungya answered the question on April 29, 2019 at 13:26

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