Find the equation of the straight line passing through the points (-3,4) and (8,1)

Find the equation of the straight line passing through the points (-3,4) and (8,1)

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Gradient = $\frac{y-y_1}{x-x_1}$

= $\frac{1-4}{8-(-3)}$ = $\frac{-3}{11}$

Pick one of the points equation is

$\frac{y-1}{x-8}$ = $\frac{-3}{11}$

11y - 11 = -3x + 24

11y + 3x = 35

y = $\frac{-3}{11}x$ + $\frac{35}{11}$

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johnmulu answered the question on June 13, 2017 at 08:30

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