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Find the equation of the straight line which passes through (2,-1) and is perpendicular to 2y = 3x + 5. Give your answer in the form of ax + by + c =0

Find the equation of the straight line which passes through (2,-1) and is perpendicular to 2y = 3x + 5. Give your answer in the form of ax + by + c =0

Answers

John
Gradient of the line

2y = 3x + 5;

y = $\frac{3}{2}x+ \frac{5}{2}$

$m_1$ = gradient = $\frac{3}{2}$

For perpendicular lines

$m_1m_2=-1$ $m_2 = - \frac{2}{3}$

The equation of the line

through (2,-1) is $\frac{y+1}{x-2}$ = - $\frac{2}{3}$

3y + 3 = -2x + 4; 3y = -2x + 4 - 3

3y = -2x + 1;

2x + 3y - 1 = 0
johnmulu answered the question on June 13, 2017 at 09:12

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