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Find the value of x when y = 6

      

A quantity x varies partly as the cube of y and partly varies inversely as the square of y. When y = 2, x = 108 and when y = 3, x = 259. Find the value of x when y = 6.

  

Answers


Raphael
$x = ky^3 + \frac{m}{y^2}$

108 = 8k + $\frac{m}{4}$

259 = 27k + $\frac{m}{9}$

k = 9

m = 144

$x = 9y^3 + \frac{144}{y^2}$

When y = 6, x = 1948
raphael answered the question on January 6, 2017 at 14:36


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