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A perpendicular is drawn from a point (3,5) to the line x + 2y = 3.

A perpendicular is drawn from a point (3,5) to the line x + 2y = 3. Find the equation of the perpendicular.

Answers

John
Gradient of x + 2y = 3

x + 2y = 3;

2y = -x + 3

y = - $\frac{x}{2}$ + $\frac{3}{2}$;

$m_1 \; = - \frac{1}{2}$

For perpendicular lines

$m_1m_2$ = -1, equation of the

perpendicular from (3,5) is

$\frac{y-5}{x-3}$ = 2

y = 2x - 6 + 5;

y = 2x - 1
johnmulu answered the question on June 13, 2017 at 09:39

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