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A line passing through the point A(4,-3) and B(6,-6) is perpendicular to px + 6y = -2. What is the value of p.

A line passing through the point A(4,-3) and B(6,-6) is perpendicular to px + 6y = -2. What is the value of p.

Answers

John
Gradient of the line

px + 6y = -2 is

6y =-px -2 is

y = -$\frac{px}{6}$ - $\frac{1}{3}$

m = -$\frac{p}{6}$

Gradient of the other

perpendicular line through

A(4,-3) and B(6,-6) is

$\frac{-6--3}{6-4}$ = $\frac{-6+3}{2}$ = -$\frac{3}{2}$

But $m_1m_2$ = -1

-$\frac{p}{6}$ x -$\frac{3}{2}$ = -1;

-$\frac{3p}{12}$ = -1

3p = -12;

p = -4
johnmulu answered the question on June 13, 2017 at 11:40

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